Let X be an infinite-dimensional Banach space. In 1995, settling a long outstanding problem of Pettis, Dilworth and Girardi constructed an X-valued Pettis integrable function on [0,1] whose primitive is nowhere weakly differentiable. Using their technique and some new ideas we show that ND, the set of strongly measurable Pettis integrable functions with nowhere weakly differentiable primitives, is lineable, i.e., there is an infinite dimensional vector space whose nonzero vectors belong to ND.
Bongiorno, B., Darji, U.B., Di Piazza, L. (2015). Lineability of non-differentiable Pettis primitives. MONATSHEFTE FÜR MATHEMATIK, 177(3), 345-364 [10.1007/s00605-014-0703-6].
Lineability of non-differentiable Pettis primitives
Di Piazza, L.
2015-01-01
Abstract
Let X be an infinite-dimensional Banach space. In 1995, settling a long outstanding problem of Pettis, Dilworth and Girardi constructed an X-valued Pettis integrable function on [0,1] whose primitive is nowhere weakly differentiable. Using their technique and some new ideas we show that ND, the set of strongly measurable Pettis integrable functions with nowhere weakly differentiable primitives, is lineable, i.e., there is an infinite dimensional vector space whose nonzero vectors belong to ND.File | Dimensione | Formato | |
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